How Does Compiler Convert Operator New Implicitly #1260
How does compiler convert “::operator new” implicitly?
This multiple choice question (MCQ) is related to the book/course
gs gs111 OOP Object Oriented Programming Java.
It can also be found in
gs gs111 Memory Allocation & Scope of Variable - OOPs MCQ: New Operator - Quiz No.2.
How does compiler convert “::operator new” implicitly?
::operator new( sizeof( type ) )
::operator new( sizeof( ) )
new operator :: type sizeof( type )
new sizeof( type ) operator