gs gs109 Python Sets - Python Sets - Quiz No.6
gs gs109 Python Quiz
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Question 1: What will be the output of the following Python code?
s1={3, 4} s2={1, 2} s3=set() i=0 j=0 for i in s1: for j in s2: s3.add((i,j)) i+=1 j+=1 print(s3)
{(3, 4), (1, 2)}
Error
{(4, 2), (3, 1), (4, 1), (5, 2)}
{(3, 1), (4, 2)}
Question 2: The ____________ function removes the first element of a set and the last element of a list.
remove
pop
discard
dispose
Question 3: The difference between the functions discard and remove is that:
Discard removes the last element of the set whereas remove removes the first element of the set
Discard throws an error if the specified element is not present in the set whereas remove does not throw an error in case of absence of the specified element
Remove removes the last element of the set whereas discard removes the first element of the set
Remove throws an error if the specified element is not present in the set whereas discard does not throw an error in case of absence of the specified element
Question 4: What will be the output of the following Python code?
s1={1, 2, 3} s2={3, 4, 5, 6} s1.difference(s2) s2.difference(s1){1, 2} {4, 5, 6}{1, 2} {1, 2}{4, 5, 6} {1, 2}{4, 5, 6} {4, 5, 6}
Question 5: What will be the output of the following Python code?
s1={1, 2, 3} s2={4, 5, 6} s1.isdisjoint(s2) s2.isdisjoint(s1)True FalseFalse TrueTrue TrueFalse False
Question 6: If we have two sets, s1 and s2, and we want to check if all the elements of s1 are present in s2 or not, we can use the function:
s2.issubset(s1)
s2.issuperset(s1)
s1.issuperset(s2)
s1.isset(s2)
Question 7: What will be the output of the following Python code?
s1={1, 2, 3, 8} s2={3, 4, 5, 6} s1|s2 s1.union(s2){3} {1, 2, 3, 4, 5, 6, 8}{1, 2, 4, 5, 6, 8} {1, 2, 4, 5, 6, 8}{3} {3}{1, 2, 3, 4, 5, 6, 8} {1, 2, 3, 4, 5, 6, 8}
Question 8: What will be the output of the following Python code?
a=set('abc') b=set('def') b.intersection_update(a) a bset() (‘e’, ‘d’, ‘f’}{} {}{‘b’, ‘c’, ‘a’} set()set() set()
Question 9: What will be the output of the following Python code, if s1= {1, 2, 3}?
s1.issubset(s1)
True
Error
No output
False
Question 10: What will be the output of the following Python code?
x=set('abcde') y=set('xyzbd') x.difference_update(y) x y {‘a’, ‘b’, ‘c’, ‘d’, ‘e’} {‘x’, ‘y’, ‘z’} {‘a’, ‘c’, ‘e’} {‘x’, ‘y’, ‘z’, ‘b’, ‘d’} {‘b’, ‘d’} {‘b’, ‘d’} {‘a’, ‘c’, ‘e’} {‘x’, ‘y’, ‘z’}
