vu cs507 Mid Term Subjective Solved Past Paper No.5
vu cs507 Information Systems Solved Past Papers
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If S contains all possible strings of a & b of length 3, then all the words in S* will have length divisible by 3 and will include any concatenation of a's and b's (because S did).
By the product rule, there are 2*2*2 = 8 possible words of length 3:
S = {aaa aab aba baa abb bba bab bbb}
- Cash flow statements through various transactions
- Inventory and debtor's management
- Creditors Management