The Inverse Sbox Permutation Followsbr B8217i Bi2 Xor Bi5 Xor #646
The inverse s-box permutation follows,<br /> b’i = b(i+2) XOR b(i+5) XOR b(i+7) XOR di<br /> Here di is –
This multiple choice question (MCQ) is related to the book/course
gs gs124 Introduction Cyber Security.
It can also be found in
gs gs124 Cryptography Overview, TCP/IP and Communication Networks - Overview - Quiz No.1.
The inverse s-box permutation follows,
b’i = b(i+2) XOR b(i+5) XOR b(i+7) XOR di
Here di is –
b’i = b(i+2) XOR b(i+5) XOR b(i+7) XOR di
Here di is –
di is the ith bit of a byte ‘d’ whose hex value is 0x15
di is the ith bit of a byte ‘d’ whose hex value is 0x05
di is the ith bit of a byte ‘d’ whose hex value is 0x25
di is the ith bit of a byte ‘d’ whose hex value is 0x51
