Find The Error In The Decryption Pseudo Code For Rc5 8211br For #293
Find the error in the Decryption pseudo code for RC5 –<br /> for i = 1 to r do<br /> RDi-1 = ((RDi – S [2xi+1] >>> LDi ) ⊕ LDi);<br /> LDi-1 = ((LDi – S [2xi] >>> RDi-1) ⊕ RDi-1);<br /> B= RD0 + S [1];<br /> A = LD0 – S [0];</p>
This multiple choice question (MCQ) is related to the book/course
gs gs124 Introduction Cyber Security.
It can also be found in
gs gs124 Pseudorandom Number Generation and Stream Ciphers and More Block Ciphers - RC4 and RC5 - Quiz No.1.
Find the error in the Decryption pseudo code for RC5 –
for i = 1 to r do
RDi-1 = ((RDi – S [2xi+1] >>> LDi ) ⊕ LDi);
LDi-1 = ((LDi – S [2xi] >>> RDi-1) ⊕ RDi-1);
B= RD0 + S [1];
A = LD0 – S [0];
for i = 1 to r do
RDi-1 = ((RDi – S [2xi+1] >>> LDi ) ⊕ LDi);
LDi-1 = ((LDi – S [2xi] >>> RDi-1) ⊕ RDi-1);
B= RD0 + S [1];
A = LD0 – S [0];
B= RD0 + S [1];
for i = 1 to r do
LDi-1 = ((LDi – S [2xi] >>> RDi-1) ⊕ RDi-1);
A = LD0 – S [0];
