The Multiplicative Inverse Of 0x95 In Aes Where #151
The multiplicative inverse of 0x95 in AES where m(x)=x<sup>8</sup>+x<sup>4</sup>+x<sup>3</sup>+x+1 is
This multiple choice question (MCQ) is related to the book/course gs gs124 Introduction Cyber Security. It can also be found in gs gs124 Advanced Encryption Algorithm and Block Cipher Operation - The AES Algorithm - Quiz No.2.
The multiplicative inverse of 0x95 in AES where m(x)=x8+x4+x3+x+1 is
0x8F
0xF8
0x8A
0xA8