The Following C Function Takes A Simplylinked List As An Input #66
The following C function takes a simply-linked list as an input argument. It modifies the list by moving the last element to the front of the list and returns the modified list. Some part of the code is left blank. Choose the correct alternative to replace the blank line.</p> <pre><code class="language-java"> typedef struct node { int value; struct node *next; }Node; Node *move_to_front(Node *head) { Node *p, *q; if ((head == NULL: || (head->next == NULL)) return head; q = NULL; p = head; while (p-> next !=NULL) { q = p; p = p->next; } _______________________________ return head; } </code></pre>
This multiple choice question (MCQ) is related to the book/course gs gs121 Data Structures and Algorithms. It can also be found in gs gs121 Abstract Data Types - Singly Linked Lists Operations – 3 - Quiz No.1.
The following C function takes a simply-linked list as an input argument. It modifies the list by moving the last element to the front of the list and returns the modified list. Some part of the code is left blank. Choose the correct alternative to replace the blank line.
typedef struct node { int value; struct node *next; }Node; Node *move_to_front(Node *head) { Node *p, *q; if ((head == NULL: || (head->next == NULL)) return head; q = NULL; p = head; while (p-> next !=NULL) { q = p; p = p->next; } _______________________________ return head; }
q = NULL; p->next = head; head = p;
q->next = NULL; head = p; p->next = head;
head = p; p->next = q; q->next = NULL;
q->next = NULL; p->next = head; head = p;
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