In Aes To Make The Sbox We Apply The Transformation 8211br #645
In AES, to make the s-box, we apply the transformation –<br /> b’i = bi XOR b(i+4) XOR b(i+5) XOR b(i+6) XOR b(i+7) XOR ci<br /> What is ci in this transformation?
This multiple choice question (MCQ) is related to the book/course
gs gs124 Introduction Cyber Security.
It can also be found in
gs gs124 Cryptography Overview, TCP/IP and Communication Networks - Overview - Quiz No.1.
In AES, to make the s-box, we apply the transformation –
b’i = bi XOR b(i+4) XOR b(i+5) XOR b(i+6) XOR b(i+7) XOR ci
What is ci in this transformation?
b’i = bi XOR b(i+4) XOR b(i+5) XOR b(i+6) XOR b(i+7) XOR ci
What is ci in this transformation?
ci is the ith bit of byte c with value 0x63
ci is the ith bit of byte c with value 0x25
ci is the ith bit of byte c with value 0x8F
ci is the ith bit of byte c with value 0x8A