The Inverse Sbox Permutation Followsbr B8217i Bi2 Xor Bi5 Xor #156
The inverse s-box permutation follows,<br /> b’_i = b_(i+2) XOR b(i+5) XOR b_(i+7) XOR d_i<br /> Here d_i is
This multiple choice question (MCQ) is related to the book/course gs gs124 Introduction Cyber Security. It can also be found in gs gs124 Advanced Encryption Algorithm and Block Cipher Operation - The AES Algorithm - Quiz No.2.
The inverse s-box permutation follows,
b’_i = b_(i+2) XOR b(i+5) XOR b_(i+7) XOR d_i
Here d_i is
b’_i = b_(i+2) XOR b(i+5) XOR b_(i+7) XOR d_i
Here d_i is
d_i is the ith bit of a byte ‘d’ whose hex value is 0x15
d_i is the ith bit of a byte ‘d’ whose hex value is 0x05
d_i is the ith bit of a byte ‘d’ whose hex value is 0x25
d_i is the ith bit of a byte ‘d’ whose hex value is 0x51