In Aes To Make The Sbox We Apply The Transformationbr B8217i Bi #152
In AES, to make the s-box, we apply the transformation<br /> b’_i = b_i XOR b_(i+4) XOR b(i+5) XOR b_(i+6) XOR b_(i+7) XOR c_i<br /> What is c_i in this transformation?
This multiple choice question (MCQ) is related to the book/course gs gs124 Introduction Cyber Security. It can also be found in gs gs124 Advanced Encryption Algorithm and Block Cipher Operation - The AES Algorithm - Quiz No.2.
In AES, to make the s-box, we apply the transformation
b’_i = b_i XOR b_(i+4) XOR b(i+5) XOR b_(i+6) XOR b_(i+7) XOR c_i
What is c_i in this transformation?
b’_i = b_i XOR b_(i+4) XOR b(i+5) XOR b_(i+6) XOR b_(i+7) XOR c_i
What is c_i in this transformation?
c_i is the ith bit of byte c with value 0x63
c_i is the ith bit of byte c with value 0x25
c_i is the ith bit of byte c with value 0x8F
c_i is the ith bit of byte c with value 0x8A