Two resistors R1 and R2 of 5 each and R3 of 10 are in series-02081
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vu mgt601 SME Management.
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vu mgt601 Mid Term Solved Past Paper No. 1.
Question 1: Two resistors R1 and R2 of 5 each and R3 of 10 are in series. How much is RT. If we applied 80 V source across the series string, how much is the current in R3.
I = VT/RT = 80/ 20 = 4A
Answer:
RT = R1+R2+R3 = 5+5+10 = 20I = VT/RT = 80/ 20 = 4A
