Suppose you want to estimate the time required to perform a-01177
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vu edu305 Classroom Management.
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vu edu305 Mid Term Solved Past Paper No. 2.
Question 1: Suppose you want to estimate the time required to perform a certain task by the two employees. One employee's study yielded a mean of 6.4 minutes and standard deviation of 2.1 minutes with 95% confidence Interval. Other employee's study yielded a mean of 2.1 minutes and standard deviation of 6.4 minutes with confidence interval of 95%. Now how many observations you will need if desired maximum error is 10% of sample mean?(z= 1.96) Do both the employees have same number of observations?
Standard Deviation = S = 2.1mint.
z = 1.96
Error = A = 10% = 0.1
n = (zs/ax)2 = [(1.96) (2.1)/(0.1)(6.4)]2 = [4.116/0.64]2 = (6.43125)2 = 41.36
41 observations
Standard Deviation = S = 6.4mint.
z = 1.96
Error = A = 10% = 0.1
n = (zs/ax)2 = [(1.96) (6.4)/(0.1)(2.1)]2
Answer:
Employee # 1:
Mean time = X = 6.4mintsStandard Deviation = S = 2.1mint.
z = 1.96
Error = A = 10% = 0.1
n = (zs/ax)2 = [(1.96) (2.1)/(0.1)(6.4)]2 = [4.116/0.64]2 = (6.43125)2 = 41.36
41 observations
Employee # 2 :
Mean time = X = 2.1mintsStandard Deviation = S = 6.4mint.
z = 1.96
Error = A = 10% = 0.1
n = (zs/ax)2 = [(1.96) (6.4)/(0.1)(2.1)]2
